In this chapter, we provide RS Aggarwal Solutions for Class 10 Chapter 16 Co-ordinate Geometry Ex 16 C Maths for English medium students, Which will very helpful for every student in their exams. Students can download the latest RS Aggarwal Solutions for Class 10 Chapter 16 Co-ordinate Geometry Ex 16 C Maths pdf, free RS Aggarwal Solutions Class 10 Chapter 16 Co-ordinate Geometry Ex 16 C Maths book pdf download. Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 10 |

Subject | Maths |

Chapter | Chapter 16 |

Chapter Name | Coordinate Geometry |

Exercise | 16 C |

Category | RS Aggarwal Solutions |

**RS Aggarwal Solutions Class 10 Chapter 16 Co-ordinate Geometry** **Ex 16 C**

**Question 1:**

(i) Let A(1, 2), B(-2, 3) and C(-3, -4) be the vertices of the given ∆ ABC, then

(ii) The coordinates of vertices of ∆ ABC are A(-5, 7), B(-4, -5) and C(4, 5)

Here, x_{1 }= -5, y_{1} = 7 ; x_{2} = -4, y_{2} = -5 ; x_{3} = 4, y_{3} = 5

(iii) The coordinates of ∆ ABC are A(3, 8), B(-4, 2) and C(5, -1)

(iv) Let P(10, -6), Q(2, 5) and R(-1, 3) be the vertices of the given ∆ PQR. Then,

**Question 2:**

(i) Join A and C, then area of quad. ABCD = area of ∆ ABC + area of ∆ ACD

(ii) The vertices of quad. ABCD are A(0, 0), B(6, 0), C(4, 3) and D(0, 3)

Area of quad. ABCD = Area of ∆ ABC + Area of ∆ ACD

= 9 + 6 = 15 sq. unit

(iii) Vertices of quad. ABCD are A(1, 0), B(5, 3), C(2, 7) and D(-2, 4)

Vertices of ∆ABC are A(1, 0), B(5, 3), C(2, 7)

Vertices of ∆ACD are A(1, 0), C(2, 7) and D(-2, 4)

Area of quadrilateral ABCD

**Question 3:**

(i) Let A(0, 1), B(1, 2) and C(-2, -1) be the given points. Then,

Hence the given points are collinear

(ii) Let A(-5, 1), B(5,5) and C(10, 7) be the given points.

(iii) Let P(a, b + c), Q(b, c + a) and R(c, a + B) be the given points.

**Question 4:**

(i) The given points are A(-1, 3), B(2, p) and C(5, -1)

(ii) The given points are A(3, 2), B(4, p) and C(5, 3)

(iii) The three points are A(-3, 9), B(2, p), C(4, -5)

**Question 5:**

The given points are A(-3, 12), B(7, 6) and C(x, 9)

**Question 6:**

Let P(1, 4), Q(3, y) and R(-3, 16)

**Question 7:**

The given points are A(x, y), B(-5, 7) and C9-4, 5)

The given points A, B, C are collinear

**Question 8:**

The vertices of a quadrilateral ABCD are (-4, -2), B(-3, -5), C(3, -2) and D(2, k)

Join AC.

Area of quadrilateral ABCD = Area of ∆ABC + Area of ∆ACD

Now area of ∆ABC

**Question 9:**

The vertices of ABC are A(4, -6), B(3, -2), C(5, 2)

AD is the median.

D is the midpoint of BC.

the coordinates of point D are

Vertices of ABD are A(4, -6), B(3, -2), D(4, 0)

Area of ∆ABD

**Question 10:**

Vertices of ∆ABC are A(2, 1), B(x, y) and C(7, 5)

The points A, B and C are collinear

area of ∆ABC = 0

Or 4x – 5y – 3 = 0

**Question 11:**

The vertices of ∆ABC are (a, 0), (0, b), C(1, 1)

The points A, B, C are collinear

Area of ∆ABC = 0

ab – a – b = 0 a + b = ab

Dividing by ab

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