RS Aggarwal Solutions Class 10 Chapter 3 Linear equations in two variables EX 3B

In this chapter, we provide RS Aggarwal Solutions for Class 10 Chapter 3 Linear equations in two variables EX 3B Maths for English medium students, Which will very helpful for every student in their exams. Students can download the latest RS Aggarwal Solutions for Class 10 Chapter 3 Linear equations in two variables EX 3B Maths pdf, free RS Aggarwal Solutions Class 10 Chapter 3 Linear equations in two variables EX 3B Maths book pdf download. Now you will get step by step solution to each question.

TextbookNCERT
ClassClass 10
SubjectMaths
ChapterChapter 3
Chapter NameLinear equations in two variables
Exercise3 B
CategoryRS Aggarwal Solutions

RS Aggarwal Solutions Class 10 Chapter 3 Linear equations in two variables Ex 3B

Question 1:

RS Aggarwal Solutions Class 10 Chapter 3 Linear equations in two variables ex 3b

Question 2:

RS Aggarwal Solutions Class 10 Chapter 3 Linear equations in two variables ex 3b

Question 3:

RS Aggarwal Solutions Class 10 Chapter 3 Linear equations in two variables ex 3b

Question 4:

RS Aggarwal Class 10 Solutions Chapter 3 Linear equations in two variables ex 3b

Question 5:

RS Aggarwal Class 10 Solutions Chapter 3 Linear equations in two variables ex 3b

Question 6:

RS Aggarwal Class 10 Solutions Chapter 3 Linear equations in two variables ex 3b

Question 7:

Solution of RS Aggarwal Class 10 Chapter 3 Linear equations in two variables ex 3b

Question 8:

Solution of RS Aggarwal Class 10 Chapter 3 Linear equations in two variables ex 3b

Question 9:

Solution of RS Aggarwal Class 10 Chapter 3 Linear equations in two variables ex 3b

Question 10:

RS Aggarwal Solutions Class 10 2017 Chapter 3 Linear equations in two variables ex 3b

Question 11:

RS Aggarwal Solutions Class 10 2017 Chapter 3 Linear equations in two variables ex 3b

Question 12:

RS Aggarwal Solutions Class 10 2017 Chapter 3 Linear equations in two variables ex 3b

Question 13:

Class 10 RS Aggarwal Solutions Chapter 3 Linear equations in two variables ex 3b

Question 14:

Class 10 RS Aggarwal Solutions Chapter 3 Linear equations in two variables ex 3b

Question 15:

Class 10 RS Aggarwal Solutions Chapter 3 Linear equations in two variables ex 3b

Question 16:

RS Aggarwal Class 10 Maths Book Solutions pdf Chapter 3 Linear equations in two variables ex 3b

Question 17:

RS Aggarwal Class 10 Maths Book Solutions pdf Chapter 3 Linear equations in two variables ex 3b

Question 18:

RS Aggarwal Class 10 Maths Book Solutions pdf Chapter 3 Linear equations in two variables ex 3b

Question 19:

RS Aggarwal Class 10 Book pdf download Chapter 3 Linear equations in two variables ex 3b

Question 20:

RS Aggarwal Class 10 Book pdf download Chapter 3 Linear equations in two variables ex 3b

Question 21:

RS Aggarwal Class 10 Book pdf download Chapter 3 Linear equations in two variables ex 3b

Question 22:

Class 10 Maths RS Aggarwal Solutions Chapter 3 Linear equations in two variables ex 3b

Taking L.C.M, we get

Class 10 Maths RS Aggarwal Solutions Chapter 3 Linear equations in two variables ex 3b

Multiplying (1) by 1 and (2) by

Class 10 Maths RS Aggarwal Solutions Chapter 3 Linear equations in two variables ex 3b

Subtracting (4) from (3), we get

Maths RS Aggarwal Class 10 Solutions Chapter 3 Linear equations in two variables ex 3b

Substituting x = ab in (3), we get

Maths RS Aggarwal Class 10 Solutions Chapter 3 Linear equations in two variables ex 3b

Therefore solution is x = ab, y = ab
Question 23:
6(ax + by) = 3a + 2b
6ax + 6by = 3a + 2b —(1)
6(bx – ay) = 3b – 2a
6bx – 6ay = 3b- 2a —(2)
6ax + 6by = 3a + 2b —(1)
6bx – 6ay = 3b – 2a —(2)
Multiplying (1) by a and (2) by b

Maths RS Aggarwal Class 10 Solutions Chapter 3 Linear equations in two variables ex 3b

Adding (3) and (4), we get

RS Aggarwal Solutions Class 10 2018 Chapter 3 Linear equations in two variables ex 3b

Substituting in (1), we get

RS Aggarwal Solutions Class 10 2018 Chapter 3 Linear equations in two variables ex 3b

Hence, the solution is

RS Aggarwal Solutions Class 10 2018 Chapter 3 Linear equations in two variables ex 3b

Question 24:

RS Aggarwal Solutions Class 10 Chapter 3 Linear equations in two variables ex 3b

Question 25:
The given equations are
71x + 37y = 253 —(1)
37x + 71y = 287 —(2)
Adding (1) and (2)
108x + 108y = 540
108(x + y) = 540

RS Aggarwal Solutions Class 10 Chapter 3 Linear equations in two variables ex 3b

—-(3)
Subtracting (2) from (1)
34x – 34y = 253 – 287 = -34
34(x – y) = -34

RS Aggarwal Solutions Class 10 Chapter 3 Linear equations in two variables ex 3b

—(4)
Adding (3) and (4)
2x = 5 – 1= 4

RS Aggarwal Solutions Class 10 Chapter 3 Linear equations in two variables ex 3b

Subtracting (4) from (3)
2y = 5 + 1 = 6

RS Aggarwal Class 10 Solutions Chapter 3 Linear equations in two variables ex 3b

Hence solution is x = 2, y = 3
Question 26:
37x + 43y = 123 —-(1)
43x + 37y = 117 —-(2)
Adding (1) and (2)
80x + 80y = 240
80(x + y) = 240
x + y = 

RS Aggarwal Class 10 Solutions Chapter 3 Linear equations in two variables ex 3b

—-(3)
Subtracting (1) from (2),
6x – 6y = -6
6(x – y) = -6

RS Aggarwal Class 10 Solutions Chapter 3 Linear equations in two variables ex 3b

—-(4)
Adding (3) and (4)
2x = 3 – 1 = 2

RS Aggarwal Class 10 Solutions Chapter 3 Linear equations in two variables ex 3b

Subtracting (4) from (3),
2y = 3 + 1 = 4

RS Aggarwal Class 10 Solutions Chapter 3 Linear equations in two variables ex 3b

Hence solution is x = 1, y = 2
Question 27:
217x + 131y = 913 —(1)
131x + 217y = 827 —(2)
Adding (1) and (2), we get
348x + 348y = 1740
348(x + y) = 1740
x + y = 5 —-(3)
Subtracting (2) from (1), we get
86x – 86y = 86
86(x – y) = 86
x – y = 1 —(4)
Adding (3) and (4), we get
2x = 6
x = 3
putting x = 3 in (3), we get
3 + y = 5
y = 5 – 3 = 2
Hence solution is x = 3, y = 2
Question 28:
41x – 17y = 99 —(1)
17x – 41y = 75 —(2)
Adding (1) and (2), we get
58x – 58y = 174
58(x – y) = 174
x – y = 3 —(3)
subtracting (2) from (1), we get
24x + 24y = 24
24(x + y) = 24
x + y = 1 —(4)
Adding (3) and (4), we get
2x = 4 x = 2
Putting x = 2 in (3), we get
2 – y = 3
-y = 3 – 2 y = -1
Hence solution is x =2, y = -1

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