# RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9 D

In this chapter, we provide RS Aggarwal Solutions for Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9 D Maths for English medium students, Which will very helpful for every student in their exams. Students can download the latest RS Aggarwal Solutions for Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9 D Maths pdf, free RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9 D Maths book pdf download. Now you will get step by step solution to each question.

Question 1:
Let assumed mean be 35, h = 10, now we have

(i) Mean

(ii) N = 100, N2= 50
Cumulative frequency just after 50 is 63
Median class is 30 – 40
l = 30, h = 10, N = 100, c = 33, f = 30

(iii) Mode = 3 × median – 2 × mean
= 3 × 35.67 – 2 × 35.6 = 107.01 – 71.2
= 35.81
Thus, Mean = 35.6, Median = 35.67 and Mode = 35.81
Question 2:
Let assumed mean A be 8.5. Class interval h = 3

N = total frequency = 100
(i) Mean

(ii) N2= 50, Cumulative frequency just after 50 is 76
Median class is 7 – 10
l = 7, h = 3, N = 100, f = 40, c = 36

(iii) Mode = 3 × Median – 2 × Mean
= 3 × 8.05 – 2 × 8.32 = 24.15 – 16.64
= 7.51
Thus, mean = 8.32, Median = 8.05, Mode = 7.51
Question 3:
Let the assumed mean A be 145. Class interval h = 10.

(i) Mean

= 145 + 4.8 = 149.8
(ii) N = 50, N2= 25
Cumulative frequency just after 25 is 42
Corresponding median class is 150 – 160
Cumulative frequency before median class, c = 22
Median class frequency f = 20

(iii) Mode = 3 × median – 2 × mean
= 3 × 151.5 – 2 × 149.8 = 454.5 – 299.6
= 154.9
Thus, Mean = 149.8, Median = 151.5, Mode = 154.9
Question 4:
Let assumed mean A = 150 and h = 20

(i) Mean

(ii) N = 50, N2= 25
Cumulative frequency just after 25 is 26
Corresponding frequency median class is 120 – 140
So, l = 120, f = 14, h = 20, c = 12

(iii) Mode = 3 × Median – 2 × Mode
= 3 × 138.6 – 2 × 145.2
= 415.8 – 190.4
= 125.4
Hence, Mean = 145.2, Median = 138.6 and Mode = 125.4
Question 5:
Let assumed mean = 225 and h = 50

(i) Mean

(ii) N = 30, N2= 15
Cumulative frequency just after 15 is 25
corresponding class interval is 200 – 250
Median class is 200 – 250
Cumulative frequency c just before this class = 13
So I=200, f=12, N2= 15, h=50, c=13

Hence, Mean = 205 and Median = 208.33

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