In this chapter, we provide RS Aggarwal Solutions for Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9 D Maths for English medium students, Which will very helpful for every student in their exams. Students can download the latest RS Aggarwal Solutions for Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9 D Maths pdf, free RS Aggarwal Solutions Class 10 Chapter 9 Mean, Median, Mode of Grouped Data Ex 9 D Maths book pdf download. Now you will get step by step solution to each question.
| Textbook | NCERT |
| Class | Class 10 |
| Subject | Maths |
| Chapter | Chapter 9 |
| Chapter Name | Mean, Median, Mode of Grouped Data |
| Exercise | 9 D |
| Category | RS Aggarwal Solutions |
Question 1:
Let assumed mean be 35, h = 10, now we have
| Class | Frequency fi | Mid value xi | ui=(xi−Ah) | C.F | fi ui |
| 0 – 1010 – 2020 – 3030 – 4040 – 5050 – 6060 – 70 | 510183020125 | 5152535 = A455565 | -3-2-10123 | 51533638395100 | -15-20-180202415 |
| N=100 | ∑(fiui)=6 |
(i) Mean
= 
(ii) N = 100, N2= 50
Cumulative frequency just after 50 is 63
Median class is 30 – 40
l = 30, h = 10, N = 100, c = 33, f = 30
(iii) Mode = 3 × median – 2 × mean
= 3 × 35.67 – 2 × 35.6 = 107.01 – 71.2
= 35.81
Thus, Mean = 35.6, Median = 35.67 and Mode = 35.81
Question 2:
Let assumed mean A be 8.5. Class interval h = 3
| Class | Frequency fi | Mid value xi | ui=(xi−Ah) | fi ui | C.F |
| 1-44-77-1010-1313-1616-19 | 630401644 | 2.55.58.5 = A11.514.517.5 | -2-10123 | -12-30016812 | 636769296100 |
| N=100 | ∑(fiui)=-6 |
N = total frequency = 100
(i) Mean
= 
(ii) N2= 50, Cumulative frequency just after 50 is 76
Median class is 7 – 10
l = 7, h = 3, N = 100, f = 40, c = 36
(iii) Mode = 3 × Median – 2 × Mean
= 3 × 8.05 – 2 × 8.32 = 24.15 – 16.64
= 7.51
Thus, mean = 8.32, Median = 8.05, Mode = 7.51
Question 3:
Let the assumed mean A be 145. Class interval h = 10.
| Class | Frequency fi | Mid value xi | ui=(xi−Ah) | fi ui | C.F |
| 120-130130-140140-150150-160160-170 | 2812208 | 125135145=A155165 | -2-1012 | -4-802016 | 210224250 |
| N=50 | ∑(fiui)=24 |
(i) Mean
= 
= 145 + 4.8 = 149.8
(ii) N = 50, N2= 25
Cumulative frequency just after 25 is 42
Corresponding median class is 150 – 160
Cumulative frequency before median class, c = 22
Median class frequency f = 20
(iii) Mode = 3 × median – 2 × mean
= 3 × 151.5 – 2 × 149.8 = 454.5 – 299.6
= 154.9
Thus, Mean = 149.8, Median = 151.5, Mode = 154.9
Question 4:
Let assumed mean A = 150 and h = 20
| Class | Frequency fi | Mid value xi | ui=(xi−Ah) | fi ui | C.F |
| 100-120120-140140-160160-180180-200 | 12148610 | 110130150= A170190 | -2-1012 | -24-140620 | 1226344050 |
| N=50 | ∑(fiui)=-12 |
(i) Mean
(ii) N = 50, N2= 25
Cumulative frequency just after 25 is 26
Corresponding frequency median class is 120 – 140
So, l = 120, f = 14, h = 20, c = 12
(iii) Mode = 3 × Median – 2 × Mode
= 3 × 138.6 – 2 × 145.2
= 415.8 – 190.4
= 125.4
Hence, Mean = 145.2, Median = 138.6 and Mode = 125.4
Question 5:
Let assumed mean = 225 and h = 50
| Class | Frequency fi | Mid value xi | ui=(xi−Ah) | fi ui | C.F |
| 100-150150-200200-250250-300300-350 | 671232 | 125175225275325 | -2-1012 | -12-7034 | 613252830 |
| N=30 | ∑(fiui)=-12 |
(i) Mean
= 
(ii) N = 30, N2= 15
Cumulative frequency just after 15 is 25
corresponding class interval is 200 – 250
Median class is 200 – 250
Cumulative frequency c just before this class = 13
So I=200, f=12, N2= 15, h=50, c=13
Hence, Mean = 205 and Median = 208.33
All Chapter RS Aggarwal Solutions For Class 10 Maths
—————————————————————————–
All Subject NCERT Exemplar Problems Solutions For Class10
All Subject NCERT Solutions For Class 10
*************************************************
I think you got complete solutions for this chapter. If You have any queries regarding this chapter, please comment on the below section our subject teacher will answer you. We tried our best to give complete solutions so you got good marks in your exam.
If these solutions have helped you, you can also share rsaggarwalsolutions.in to your friends.