In this chapter, we provide RS Aggarwal Solutions for Class 6 Chapter 4 Integers Exercise 4D for English medium students, Which will very helpful for every student in their exams. Students can download the latest RS Aggarwal Solutions for Class 6 Chapter 4 Integers Exercise 4D pdf, free RS Aggarwal Solutions Class 6 Chapter 4 Integers Exercise 4D book pdf download. Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 6 |

Subject | Maths |

Chapter | Chapter 4 |

Chapter Name | Integers |

Exercise | 4D |

Category | RS Aggarwal Solutions |

**RS Aggarwal Class 6 Chapter 4 Integers Ex 4D Download PDF**

**Question 1.****Solution:**

(i) 15 by 9 = 15 x 9 = 135

(ii) 18 by – 7 = 18 x ( – 7) = – 126

(iii) 29 by – 11 = 29 x ( – 11) = – 319

(iv) – 18 by 13 = ( – 18) x 13 = – 234

(v) – 56 by 16 = ( – 56) x 16 = – 896

(vi) 32 by – 21 = 32 x ( – 21) = – 672

(vii) – 57 x 0 = ( – 57) x 0 = 0

(viii) 0 by – 31 = 0 x ( – 31) = 0

(ix) – 12 by – 9 = ( – 12) x ( – 9) = 108

(x) – 746 by – 8 = ( – 746) x ( – 8) = 5968

(xi) 118 by – 7 = 118 x ( – 7) = – 826

(xii) – 238 by – 143 = ( – 238) x ( – 143) = 238 x 143 = 34034

**Question 2.****Solution:**

(i) ( – 2) x 3 x ( – 4) = [( – 2) x 3] x ( – 4) = ( – 6) x ( – 4) = 24

(ii) 2 x ( – 5) x ( – 6) = 2 x [( – 5) x ( – 6)] = 2 x 30 = 60

(iii) ( – 8) x 3 x 5 = ( – 8) x (3 x 5) = ( – 8) x 15 = – 120

(iv) 8 x 7 x ( – 10) = (8 x 7) x ( – 10) = 56 x ( – 10) = – 560

(v) ( – 3) x ( – 7) x ( – 6) = [( – 3) x ( – 7)] x ( – 6) = 21 x ( – 6) = – 126

(vi) ( – 8) x ( – 3) x ( – 9) = ( – 8) x [( – 3) x ( – 9)] = ( – 8) x 27 = – 216

**Question 3.****Solution:**

(i) 18 x ( – 27) x 30 = 18 x [( – 27) x 30] = 18 x ( – 810) = – 14580

(ii) ( – 8) x ( – 63) x 9 = [( – 8) x ( – 63)] x 9 = 504 x 9 = 4536

(iii) ( – 17) x ( – 23) x 41 = [( – 17) x ( – 23)] x 41 = 391 x 41 = 16031

(iv) ( – 51) x ( – 47) x ( – 19) = [( – 51) x ( – 47)] x ( – 19) = 2397 x ( – 19) = – 45543

**Question 4.****Solution:**

(i) We have :

18 x [9 + ( – 7)] = 18 x 2 = 36

18 x 9 + 18 x ( – 7)

= (18 x 9) + [18 x ( – 7)]

= 162 – 126

= 36

18 x [9 x ( – 7)] = 18 x 9 + 18 x ( – 7) is verified.

(ii) We have :

( – 13) x [( – 6) x ( – 19)]

= ( – 13) x ( – 25) = 325

( – 13) x ( – 6) + ( – 13) x – 9

= [( – 13) x ( – 6)] + [( – 13) x ( – 19)]

= 78 + 247 = 325

( – 13) x [( – 6) + ( – 19)]

= ( – 13) x ( – 6) + ( – 13) x ( – 19) is verified.

**Question 5.****Solution:**

The complete multiplication table is given below

**Question 6.****Solution:**

(i) True

(ii) False

(iii) True

(iv) True

**Question 7.****Solution:**

(i) ( – 9) x 6 + ( – 9) x 4

= ( – 9) x (6 + 4)

(By distributive law)

= ( – 9) x 10

= – 90

(ii) 8 x ( – 12) + 7 x ( – 12)

= ( 8 + 7) x ( – 12)

(By distributive law)

= 15 x ( – 12)

= – 180

(iii) 30 x ( – 22) + 30 x (14)

= 30 x [( – 22) + 14]

(By distributive law)

= 30 x ( – 8)

= – 240

(iv) ( – 15) x ( – 14) + ( – 15) x ( – 6)

= ( – 15) x [( – 14) + ( – 6)]

(By distributive law)

= ( – 15) x ( – 20)

= 300

(v) 43 x ( – 33) + 43 x ( – 17)

= 43 x [( – 33) + ( – 17)]

(By distributive law)

= 43 x ( – 50) = – 2150

(vi) ( – 36) x 72 + ( – 36) x 28

= ( – 36) x (72 + 28)

(By distributive law)

= ( – 36) x 100

= – 3600

(vii)( – 27) x ( – 16) + ( – 27) x ( – 14)

= ( – 27) x [( – 16) + ( – 14)]

(By distributive law)

= ( – 27) x ( – 30)

= 810

**All Chapter RS Aggarwal Solutions For Class 6 Maths**

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**All Subject NCERT Solutions For Class 6**

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