# RS Aggarwal Solutions Class 7 Chapter 2 Fractions CCE Test Paper

In this chapter, we provide RS Aggarwal Solutions for Class 7 Chapter 2 Fractions CCE Test Paper for English medium students, Which will very helpful for every student in their exams. Students can download the latest RS Aggarwal Solutions for Class 7 Chapter 2 Fractions CCE Test Paper Maths pdf, free RS Aggarwal Solutions Class 7 Chapter 2 Fractions CCE Test Paper Maths book pdf download. Now you will get step by step solution to each question.

### RS Aggarwal Class 7 Solutions Chapter 2 Fractions CCE Test Paper Download PDF

Question 1.
Solution:
(i) A number of the form ab, where a and b are rational numbers, is called a natural number.
Here, a is the numerator and b is the denominator.
(a) 2/3 is a fraction with 2 as the numerator and 3 as the denominator.
(b) 1/25 is a fraction with 12 as the numerator and 5 as the denominator.
(ii) A fraction whose denominator is a whole number other than 10, 100, 1000, etc., is called a vulgar faction.
Examples : 2/5 and 4/15.
(iii) A fraction whose numerator is greater than or equal to its denominator is called an improper fraction.
Example : 1/13 and 41/35

Question 2.
Solution: Hence, the required number is 8/25

Question 3.
Solution: Question 4.
Solution: Question 5.
Solution:  Question 6.
Solution: Question 7.
Solution:  Question 8.
Solution:  Question 9.
Solution: Mark (√) against the correct answer in each of the following:

Question 10.

Solution:
(d) 58
58 is a vulgar fraction, because its denominator is other than 10,100, 1000, etc.

Question 11.
Solution:
(c) 4663
A fraction ab is said to be irreducible or in its lowest terms if the HCF of a and b is 1
46 = 2 x 23 x 1
63 = 3 x 3 x 21 x 1
Clearly, the HCF of 46 and 63 is 1.
Hence, 4663 is an irreducible fraction.

Question 12.
Solution:
(d) None of these
Reciprocal of 135 = Reciprocal of 85 = 58

Question 13.
Solution: Question 14.
Solution:  Question 15.
Solution: Question 16.
Solution:
(b) 33 km
Distance covered by the car on Question 17.
Solution:  Question 18.
Solution:
(i) False.
By cross multiplication, we have:
9 x 24 = 216 and 13 x 16 = 208
However, 216 > 208
916 > 1324  All Chapter RS Aggarwal Solutions For Class 7 Maths

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All Subject NCERT Exemplar Problems Solutions For Class 7

All Subject NCERT Solutions For Class 7

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