In this chapter, we provide RS Aggarwal Solutions for Class 7 Chapter 20 Mensuration Ex 20E for English medium students, Which will very helpful for every student in their exams. Students can download the latest RS Aggarwal Solutions for Class 7 Chapter 20 Mensuration Ex 20E Maths pdf, free RS Aggarwal Solutions Class 7 Chapter 20 Mensuration Ex 20E Maths book pdf download. Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 7 |

Subject | Maths |

Chapter | Chapter 20 |

Chapter Name | Mensuration |

Exercise | 20E |

**RS Aggarwal Solutions for Class 7 Chapter 20 Mensuration Ex 20E Download PDF**

**Question 1.****Solution:**

Radius of the circle (r) = 28 cm

**Question 2.****Solution:**

(i) Diameter of circle (d) = 35 cm

**Question 3.****Solution:**

Radius of a circle = 15 cm

Circumference = 2πr = 2 x 3.14 x 15 = 94.20 cm = 94.2 cm

**Question 4.****Solution:**

Circumference of a circle (c) = 57.2 cm

**Question 5.****Solution:**

Circumference (c) = 63.8 m

**Question 6.****Solution:**

Let c be the circumference and d be the diameter of the circle.

c = d + 30

⇒ dπ = d + 30

⇒ dπ – d = 30

⇒ d (π – 1) = 30

**Question 7.****Solution:**

The ratio of the radii of the circles = 5 : 3

Let radius of first circle = 5x

and radius of second circle = 3x

Circumference of first circle = 2πr = 2π x 5x = 10πx

and circumference of second circle = 2π x 3x = 6πx

Ratio = 10πx : 6πx = 10 : 6 = 5 : 3

**Question 8.****Solution:**

Radius of circular field (r) = 21 m

Circumference = 2πr

**Question 9.****Solution:**

Outer circumference = 616 m

Width of track = R – r = 98 – 84 = 14m

**Question 10.****Solution:**

Inner circumference of the circular track = 330 m

Rate of fencing = Rs. 20 per metre

Total cost = Rs. 20 x 396 = Rs. 7920

**Question 11.****Solution:**

Radius of inner circle (r) = 98 cm

Inner circumference = 2πr = 2 x 227 x 98 cm = 616 cm

Radius of the outer circle (R) = 1 m 26cm = 126 cm

Outer circumference = 2πR = 2 x 227 x 126 cm = 792 cm

**Question 12.****Solution:**

Side of equilateral triangle = 8.8 cm

Its perimeter = 8.8 x 3 = 26.4 cm

By bending their wire into a circular shape,

the circumference = 26.4 cm

Let d be the diameter,

Then C = dπ

**Question 13.****Solution:**

Each side of rhombus = 33 cm

Perimeter = 4 x 33 = 132 cm

Perimeter of circle = 132 cm

Let r be the radius

**Question 14.****Solution:**

Length of rectangle (l) = 18.7 cm

Breadth (b) = 14.3 cm

Perimeter = 2 (l + b) = 2 (18.7 + 14.3) cm = 2 x 33 = 66 cm

Circumference of the so formed circle = 66 cm

**Question 15.****Solution:**

Radius of the circle (r) = 35 cm

Its circumference (c) = 2πr

**Question 16.****Solution:**

Diameter of well (d) = 140 cm

Outer circumference of parapet = 616 cm

Let D be the diameter, then

**Question 17.****Solution:**

Diameter of wheel (d) = 98 cm

**Question 18.****Solution:**

Diameter of cycle wheel (d) = 70 cm

**Question 19.****Solution:**

Diameter of car wheel (d) = 77 cm

Circumference = πd = 227 x 77 cm

**Question 20.****Solution:**

No. of revolutions = 5000

Distance covered = 11 km = 11 x 1000 = 11000 m

**Question 21.****Solution:**

Length of hour hand (r) = 4.2 cm

and length of minutes hand (R) = 7cm

Distance covered by hour hand in 24 hours = 2πR

= 2 x 227 x 4.2

= 26.4 cm

But distance covered by minute hand in one hour = 2πR = 2 x 227 x 7 = 44 cm

and distance covered by minute hand in 24 hours = 44 x 24 cm = 1056 cm

Sum of distance covered by these hands = 26.4 + 1056 = 1082.4 cm

**All Chapter RS Aggarwal Solutions For Class 7 Maths**

—————————————————————————–**All Subject NCERT Exemplar Problems Solutions For Class** **7**

**All Subject NCERT Solutions For Class 7**

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