In this chapter, we provide RS Aggarwal Solutions for Class 7 Chapter 20 Mensuration Ex 20F for English medium students, Which will very helpful for every student in their exams. Students can download the latest RS Aggarwal Solutions for Class 7 Chapter 20 Mensuration Ex 20F Maths pdf, free RS Aggarwal Solutions Class 7 Chapter 20 Mensuration Ex 20F Maths book pdf download. Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 7 |

Subject | Maths |

Chapter | Chapter 20 |

Chapter Name | Mensuration |

Exercise | 20F |

**RS Aggarwal Solutions for Class 7 Chapter 20 Mensuration Ex 20F Download PDF**

**Question 1.****Solution:**

(i) Radius of the circle (r) = 21 cm

**Question 2.****Solution:**

(i) Diameter of the circle = 28 cm

**Question 3.****Solution:**

Circumference of a circle = 264 cm

**Question 4.****Solution:**

Circumference of the circle (c) = 35.2 m

**Question 5.****Solution:**

Area of the circle = 616 cm²

**Question 6.****Solution:**

Area of a circle = 1386 m²

**Question 7.****Solution:**

Ratio in the radii of two circles = 4 : 5

Let radius of first circle (r1) = 4x

and radius of the second circle (r2) = 5x

**Question 8.****Solution:**

Length of rope (r) = 21 m

Area of the circle = πr² = 227 x 21 x 21 m² = 1386 m²

The horse will graze on 1386 m² area

**Question 9.****Solution:**

Area of a square made of a wire = 121 cm²

Side = √Area = √121 = 11 m

Perimeter of wire = 4 x side = 4 x 11 = 44 cm

Circumference of circular wire = 44 cm

**Question 10.****Solution:**

Radius of circular wire = 28 cm

Circumference = 2πr = 2 x 227 x 28 cm = 176 cm

Perimeter of the square formed by this wire = 176 cm

Side (a) = 1764 = 44 cm .

Area of square so formed = a² = (44)² cm² = 1936 cm²

**Question 11.****Solution:**

Length of rectangular sheet (l) = 34 cm

and breadth (b) = 24 cm

Area = l x b = 34 x 24 cm² = 816 cm²

Diameter of one button = 3.5 cm

Radius (r) = 3.52 cm

and area of one button = πr²

Area of 64 buttons = 9.625 x 64 cm² =616 cm²

Area of remaining sheet = 816 – 616 = 200 cm²

**Question 12.****Solution:**

Length of ground (l) = 90 m

and breadth (b) = 32 m

Area = l x b = 90 x 32 m² = 2880 m²

Radius of circular tank (r) = 14 m

= 616 m²

Area of remaining portion = 2880 – 616 = 2264 m²

Rate of turfing = Rs. 50 per sq.m.

Total cost = Rs. 50 x 2264 = Rs. 113200

**Question 13.****Solution:**

Each side of square = 14 cm

Area of square = a² = 14 x 14 = 196 cm²

Radius of each circle at each corner of square = 142 = 7 cm

Area of shaded portion = Area of square – area of 4 quadrants

= 196 – 154 = 42 cm²

**Question 14.****Solution:**

Length of field = 60 m

and breadth = 40 m

Length of rope = 14 m

Area covered by the horse

**Question 15.****Solution:**

Diameter of largest circle (outer circle) = 21 cm

Area of shaded portion = 346.5 – (154 + 38.5) = (346.5 – 192.5) = 154 cm²

**Question 16.****Solution:**

Length of plot (l) = 8m

and breadth (b) = 6m

Area of plot = l x b = 8 x 6 = 48 m²

Radius of each quadrant at the corner = 2 m

**All Chapter RS Aggarwal Solutions For Class 7 Maths**

—————————————————————————–**All Subject NCERT Exemplar Problems Solutions For Class** **7**

**All Subject NCERT Solutions For Class 7**

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