In this chapter, we provide RS Aggarwal Solutions for Class 7 Chapter 5 Exponents CCE Test Paper for English medium students, Which will very helpful for every student in their exams. Students can download the latest RS Aggarwal Solutions for Class 7 Chapter 5 Exponents CCE Test Paper Maths pdf, free RS Aggarwal Solutions Class 7 Chapter 5 Exponents CCE Test Paper Maths book pdf download. Now you will get step by step solution to each question.
|Exercise||CCE Test Paper|
RS Aggarwal Solutions for Class 7 Chapter 5 Exponents CCE Test Paper Download PDF
Let the required number be x
Let the required number be x.
(-20)-1 ÷ x = (-10)-1
(i) 2000000 = 2.000000 x 106 [Since the decimal point is moved 6 to the left]
= 2 x 106
(ii) 6.4 x 105 = 6.4 x 100000 = 640000
We have :
We have :
Mark (✓) against the correct answer in each of the following :
(c) 3.263 x 105
A given number is said to be in standard form if it can be expressed as
k x 10n, where k is a real number such that 1 < k < 10 and n is a positive integer.
For example : 3.263 x 105
645 = 6.45 x 102
[Since the decimal point is moved 2 places to the left]
27000 = 2.7 x 104
[Since the decimal point is moved 4 places to the left]
(3° + 4° + 5°) = 1
Reciprocal of 56 = Reciprocal of
All Subject NCERT Exemplar Problems Solutions For Class 7
All Subject NCERT Solutions For Class 7
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