In this chapter, we provide RS Aggarwal Solutions for Class 7 Chapter 8 Ratio and Proportion Ex 8C for English medium students, Which will very helpful for every student in their exams. Students can download the latest RS Aggarwal Solutions for Class 7 Chapter 8 Ratio and Proportion Ex 8C Maths pdf, free RS Aggarwal Solutions Class 7 Chapter 8 Ratio and Proportion Ex 8C Maths book pdf download. Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 7 |

Subject | Maths |

Chapter | Chapter 8 |

Chapter Name | Ratio and Proportion |

Exercise | 8C |

**RS Aggarwal Solutions for Class 7 Chapter 8 Ratio and Proportion Ex 8C Download PDF**

**Question 1.****Solution:**

(d) a : b = 3 : 4, b : c = 8 : 9

**Question 2****Solution:**

(a) A : B = 2 : 3, B : C = 4 : 5

**Question 3.****Solution:**

(d)

**Question 4.****Solution:**

(b) 15% of A = 20% of B

**Question 5.****Solution:**

(a)

**Question 6.****Solution:**

(b) A : B = 5 : 7, B : C = 6 : 11

LCM of 7, 6 = 42

**Question 7.****Solution:**

(c) 2A = 3B = 4C = x

**Question 8.****Solution:**

(a)

A3 = B4 = C5 = 1(suppose)

A = 3, B = 4, C = 5

A : B : C = 3 : 4 : 5

**Question 9.****Solution:**

(b)

**Question 10.****Solution:**

(c)

**Question 11.****Solution:**

(c) (3a + 5b) : (3a – 5b) = 5 : 1

**Question 12.****Solution:**

(c) 7 : x :: 35 : 45

x = 9

**Question 13.****Solution:**

(b) Let x to be added to each term of 3 : 5

Then 3+x5+x = 56

By cross multiplication

18 + 6x = 25 + 5x

6x – 5x = 25 – 18

x = 7

7 is to be added

**Question 14.****Solution:**

(d) Ratio in two numbers = 3 : 5

Let first number = 3x

Then second number = 5x

According to the condition,

3x+105x+10 = 57

(By cross multiplication)

25x + 50 = 21x + 70

25x – 21x = 70 – 50

4x = 20

x = 5

First number = 3 x 5 = 15

and second number = 5 x 5 = 25

Sum of numbers = 15 + 25 = 40

**Question 15.****Solution:**

(a)

Let x be subtracted from each of the term

15–x19–x = 34

⇒ 4 (15 – x) = 3 (19 – x)

⇒ 60 – 4x = 57 – 3x

⇒ -4x + 3x = 57 – 60

⇒ -x = -3

x = 3

Required number = 3

**Question 16.****Solution:**

(a)

Amount = Rs. 420

and ratio = 3 : 4

Sum of ratios = 3 + 4 = 7

A’s share = 420×37 = Rs. 60 x 3 = Rs. 180

**Question 17.****Solution:**

(d)

Let number of boys = x, then

x : 160 : : 8 : 5

⇒ x x 5 = 160 x 8

x = 160×85 = 32 x 8 = 256

Number of total students of the school = 256 + 160 = 416

**Question 18.****Solution:**

(a)

**Question 19.****Solution:**

(c)

Let x be the third proportional to 9 and 12 then

9 : 12 :: x : 12

⇒ 9 x x = 12 x 12

⇒ x = 12×129 = 1449 = 16

Third proportional = 16

**Question 20.****Solution:**

Answer = (b)

Mean proportional of 9 and 16 = √(9 x 16) = √144 = 12

**Question 21.****Solution:**

(a)

Let age of A = 3x

and age of B = 8x

6 years hence, their ages will be 3x + 6 and 8x + 6

3x+68x+6 = 49

⇒ 9 (3x + 6) = 4 (8x + 6)

⇒ 27x + 54 = 32x + 24

⇒ 32x – 27x = 54 – 24

⇒ 5x = 30

⇒ x = 6

A’s age = 3x = 3 x 6 = 18 years

**All Chapter RS Aggarwal Solutions For Class 7 Maths**

—————————————————————————–**All Subject NCERT Exemplar Problems Solutions For Class** **7**

**All Subject NCERT Solutions For Class 7**

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