# RS Aggarwal Class 7 Solutions Chapter 9 Unitary Method CCE Test Paper

In this chapter, we provide RS Aggarwal Solutions for Class 7 Chapter 9 Unitary Method CCE Test Paper for English medium students, Which will very helpful for every student in their exams. Students can download the latest RS Aggarwal Solutions for Class 7 Chapter 9 Unitary Method CCE Test Paper Maths pdf, free RS Aggarwal Solutions Class 7 Chapter 9 Unitary Method CCE Test Paper Maths book pdf download. Now you will get step by step solution to each question.

### RS Aggarwal Solutions for Class 7 Chapter 9 Unitary Method CCE Test Paper Download PDF

Question 1.
Solution:
Cost of 8 toys = ₹ 192
Cost of 1 toys = ₹ $$\frac { 192 }{ 8 }$$ = ₹ 24
Cost of 14 toys = 24 x 14 = ₹ 336

Question 2.
Solution:
Distance covered with 15L of petrol = 270 km
Distance covered with 1L of petrol 270 = $$\frac { 270 }{ 15 }$$ km
Distance covered with 8L of petrol 270 = $$\frac { 270 }{ 15 }$$ x 8 km = 144 km

Question 3.
Solution:
Cost of 15 envelopes = ₹ 11.25
Cost of 1 envelope = ₹ $$\frac { 11.25 }{ 15 }$$
Cost of 20 envelopes = $$\frac { 11.25 }{ 15 }$$ x 20 = ₹ 15

Question 4.
Solution:
24 cows can graze a field in = 20 days
1 cow can graze a field in = 20 x 24 days
15 cows can graze a field in = $$\frac { 20 x 24 }{ 15 }$$
= 32 days

Question 5.
Solution:
Time taken to finish the work by 8 men = 15 h
Time taken to finish the work by 1 man = 8 x 15 h
Time taken to finish the work by 20 men = $$\frac { 8 x 15 }{ 20 }$$ h = 6 h
[More men, less time taken]

Question 6.
Solution:
Time taken to fill $$\frac { 4 }{ 5 }$$ of the cistern = 1 min
Time taken to fill 1 cistern = $$\frac { 1 }{ \frac { 4 }{ 5 } }$$ = $$\frac { 5 }{ 4 }$$
= 1.25 min = 1 min 15 sec
Hence, it will take 1 min 15 sec to fill the empty cistern.

Question 7.
Solution:
Time taken to cover the distance at a speed of 45 km/h = 3 h 20 min
Time taken to cover the distance at a speed of 1 km/h = 45 x 3.33 h
[Less speed, more time taken] (20 min = 0.33 hour)
Time taken to cover the distance at a speed of 50 km/h
= $$\frac { 45 x 3.33 }{ 50 }$$ h
= 3h [More speed, less time taken]

Question 8.
Solution:
Number of days with enough food for 120 men = 30
Number of days with enough food for 1 man = 30 x 120 [Less men, more days]
Number of days with enough food for 100 men = $$\frac { 30 x 120 }{ 100 }$$
= 36 [More men, less days]

Mark (✓) against the correct answer in each of the following :
Question 9.
Solution:
(c) 644 km
1 cm represents km 80.5 cm represents = 8 x 80.5 = 644 km

Question 10.
Solution:
(a) 24 days
16 men can reap the field in 30 days.
1 man can reap the field in 30 x 16 days [Less men, more days]
20 men can reap the field in $$\frac { 30 x 16 }{ 20 }$$
= 24 days [More men, less days]

Question 11.
Solution:
(b) 49
Number of cows that eat as much as 15 buffaloes = 21
Number of cows that eat as much as 1 buffalo = $$\frac { 21 }{ 15 }$$
Number of cows that eat as much as 35 buffaloes = $$\frac { 21 }{ 15 }$$ x 35 = 49

Question 12.
Solution:
Number of cows that graze the field in 12 days = 45
Number of cows that graze the field in 1 day = 45 x 12
Number of cows that graze the field in 9 days = $$\frac { 45 x 12 }{ 2 }$$ = 60

Question 13.
Solution:
(b) ₹ 162
Cost of 72 eggs = ₹ 108
Cost of 1 egg = ₹ $$\frac { 108 }{ 72 }$$
Cost of 108 eggs = ₹ $$\frac { 108 x 108 }{ 72 }$$
= ₹ 162

Question 14.
Solution:
(i) 588 days
42 men can dig the trench in 14 days 1 men can dig the trench in = 42 x 14 = 588 days
(ii) ₹48
15 oranges cost ₹ 60
12 oranges will cost ₹ $$\frac { 60 }{ 15 }$$ x 12 = ₹ 48
(iii) 10.8 kg
A rod of length 10m weighs 18 kg
A rod of length 6 m will weigh = $$\frac { 18 }{ 10 }$$ x 6 = 10.8 kg
(iv) 3 h 12 min
12 workers finish the work in 4 h
15 workers will finish the work in $$\frac { 4 x 12 }{ 15 }$$ = 3.2 h = 3h 12 min

Question 15.
Solution:
(i) False
10 pipes fill the tank in = 24 min.
1 pipe will fill the tank in = 24 x 10 min. [Less pipes, more time taken]
8 pipes will fill the tank in = $$\frac { 24 x 10 }{ 8 }$$
= 30 min. [More pipes, less time taken]
(ii) True
8 men finish the work in = 40 days
1 man finishes the work in = 8 x 40 days [Less men, more days taken]
10 men will finish the work in = $$\frac { 8 x 40 }{ 10 }$$
= 32 days [More men, less days taken]
(iii) True
A 6 m tall tree casts a shadow of length = 4 m.
Aim tall tree cast a shadow of length = $$\frac { 4 }{ 6 }$$ m
A 75 m tall pole will cast a shadow of length = $$\frac { 4 }{ 6 }$$ x 75 = 50 m
(iv) True
1 toy is made in = $$\frac { 2 }{ 3 }$$ h. [Less toys, less time taken]
12 toys can be made in = $$\frac { 2 }{ 3 }$$ x 12
= 8h [More toys, more time taken]

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