RS Aggarwal Solutions Class 9 Chapter 13 Volume and Surface Area

In this chapter, we provide RS Aggarwal Solutions for Class 9 Chapter 13 Volume and Surface Area Maths for English medium students, Which will very helpful for every student in their exams. Students can download the latest RS Aggarwal Solutions for Class 9 Chapter 13 Volume and Surface Area Maths pdf, free RS Aggarwal Solutions Class 9 Chapter 13 Volume and Surface Area Maths book pdf download. Now you will get step by step solution to each question.

RS Aggarwal Solutions Class 9 Chapter 13 Volume and Surface Area

RS Aggarwal Solutions Class 9 Chapter 13 Exercise 13A

Question 1:
(i) length =12cm, breadth = 8 cm and height = 4.5 cm
∴ Volume of cuboid = l x b x h
= (12 x 8 x 4.5) cm³= 432 cm³
∴ Lateral surface area of a cuboid = 2(l + b) x h
= [2(12 + 8) x 4.5] cm²
= (2 x 20 x 4.5) cm² = 180 cm²
∴ Total surface area cuboid = 2(lb +b h+ l h)
= 2(12 x 8 + 8 x 4.5 + 12 x 4.5) cm²
= 2(96 +36 +54) cm²
= (2 x186) cm²
= 372 cm²

(ii) Length 26 m, breadth =14 m and height =6.5 m
∴ Volume of a cuboid = l x b x h
= (26 x 14 x 6.5) m³
= 2366 m³
∴ Lateral surface area of a cuboid =2 (l + b) x h
= [2(26+14) x 6.5] m²
= (2 x 40 x 6.5) m²
= 520 m²
∴ Total surface area = 2(lb+ bh + lh)
= 2(26 x 14+14 x6.5 +26 x6.5)
= 2 (364+91+169) m²
= (2 x 624) m2= 1248 m².

(iii) Length = 15 m, breadth = 6m and height = 5 dm = 0.5 m
∴ Volume of a cuboid = l x b x h
= (15 x 6 x 0.5) m3=45 m³.
∴ Lateral surface area = 2(l + b) x h
= [2(15 + 6) x 0.5] m²
= (2 x 21×0.5) m2=21 m²
∴ Total surface area =2(lb+ bh + lh)
= 2(15 x 6 +6 x 0.5+ 15 x 0.5) m²
= 2(90+3+7.5) m²
= (2 x 100.5) m²
=201 m²

(iv) Length = 24 m, breadth = 25 cm =0.25 m, height = 6m.
∴ Volume of cuboid = l x b x h
= (24 x 0.25 x 6) m³.
= 36 m³.
∴ Lateral surface area = 2(l + b) x h
= [2(24 +0.25) x 6] m²
= (2 x 24.25 x 6) m²
= 291 m².
∴ Total surface area =2(lb+ bh + lh)
=2(24 x 0.25+0.25x 6 +24 x 6) m²
= 2(6+1.5+144) m²
= (2 x151.5) m² 
=303 m².

Question 2:
Length of Cistern = 8 m
Breadth of Cistern = 6 m
And Height (depth) of Cistern =2.5 m
∴ Capacity of the Cistern = Volume of cistern
∴ Volume of Cistern = (l x b x h)
= (8 x 6 x2.5) m³
=120 m³
Area of the iron sheet required = Total surface area of the cistem.
∴ Total surface area = 2(lb +bh +lh)
= 2(8 x 6 + 6×2.5+ 2.5×8) m²
= 2(48 + 15 + 20) m²
= (2 x 83) m2=166 m²

Question 3:
Length of a room =9m,
Breadth of a room = 8m
And height of room = 6.5 m
∴ Area of 4 walls = Lateral surface area
= 2 (l+ b) x h
= [2 (9+8) x 6.5] m²
= (2 x 17 x 6.5) m²
=221 m²
∴ Area not be whitewashed = (area of 1 door) + (area of 2 windows)
= (2 x 1.5) m² + (2 x 1.5 x 1) m²
= 3m² + 3m² =6m²
∴ Area to be whitewashed = (221-6) m² =215 m²
∴ Cost of whitewashing the walls at the rate of Rs.6.40 per
Square meter = Rs. (6.40 x 215) = Rs. 1376

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RS Aggarwal Solutions Class 9 Chapter 13 Exercise 13B

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RS Aggarwal Solutions Class 9 Chapter 13 Exercise 13C

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RS Aggarwal Solutions Class 9 Chapter 13 Exercise 13D

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All Chapter RS Aggarwal Solutions For Class 9 Maths

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All Subject NCERT Exemplar Problems Solutions For Class 9

All Subject NCERT Solutions For Class 9

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