# RS Aggarwal Solutions Class 9 Chapter 13 Volume and Surface Area

In this chapter, we provide RS Aggarwal Solutions for Class 9 Chapter 13 Volume and Surface Area Maths for English medium students, Which will very helpful for every student in their exams. Students can download the latest RS Aggarwal Solutions for Class 9 Chapter 13 Volume and Surface Area Maths pdf, free RS Aggarwal Solutions Class 9 Chapter 13 Volume and Surface Area Maths book pdf download. Now you will get step by step solution to each question.

## RS Aggarwal Solutions Class 9 Chapter 13 Volume and Surface Area

### RS Aggarwal Solutions Class 9 Chapter 13Exercise 13A

Question 1:
(i) length =12cm, breadth = 8 cm and height = 4.5 cm
∴ Volume of cuboid = l x b x h
= (12 x 8 x 4.5) cm3= 432 cm3
∴ Lateral surface area of a cuboid = 2(l + b) x h
= [2(12 + 8) x 4.5] cm2
= (2 x 20 x 4.5) cm2 = 180 cm2
∴ Total surface area cuboid = 2(lb +b h+ l h)
= 2(12 x 8 + 8 x 4.5 + 12 x 4.5) cm2
= 2(96 +36 +54) cm2
= (2 x186) cm2
= 372 cm2

(ii) Length 26 m, breadth =14 m and height =6.5 m
∴ Volume of a cuboid = l x b x h
= (26 x 14 x 6.5) m3
= 2366 m3
∴ Lateral surface area of a cuboid =2 (l + b) x h
= [2(26+14) x 6.5] m2
= (2 x 40 x 6.5) m2
= 520 m2
∴ Total surface area = 2(lb+ bh + lh)
= 2(26 x 14+14 x6.5 +26 x6.5)
= 2 (364+91+169) m2
= (2 x 624) m2= 1248 m2.

(iii) Length = 15 m, breadth = 6m and height = 5 dm = 0.5 m
∴ Volume of a cuboid = l x b x h
= (15 x 6 x 0.5) m3=45 m3.
∴ Lateral surface area = 2(l + b) x h
= [2(15 + 6) x 0.5] m2
= (2 x 21×0.5) m2=21 m2
∴ Total surface area =2(lb+ bh + lh)
= 2(15 x 6 +6 x 0.5+ 15 x 0.5) m2
= 2(90+3+7.5) m2
= (2 x 100.5) m2
=201 m2

(iv) Length = 24 m, breadth = 25 cm =0.25 m, height = 6m.
∴ Volume of cuboid = l x b x h
= (24 x 0.25 x 6) m3.
= 36 m3.
∴ Lateral surface area = 2(l + b) x h
= [2(24 +0.25) x 6] m2
= (2 x 24.25 x 6) m2
= 291 m2.
∴ Total surface area =2(lb+ bh + lh)
=2(24 x 0.25+0.25x 6 +24 x 6) m2
= 2(6+1.5+144) m2
= (2 x151.5) m
=303 m2.

Question 2:
Length of Cistern = 8 m
Breadth of Cistern = 6 m
And Height (depth) of Cistern =2.5 m
∴ Capacity of the Cistern = Volume of cistern
∴ Volume of Cistern = (l x b x h)
= (8 x 6 x2.5) m3
=120 m3
Area of the iron sheet required = Total surface area of the cistem.
∴ Total surface area = 2(lb +bh +lh)
= 2(8 x 6 + 6×2.5+ 2.5×8) m2
= 2(48 + 15 + 20) m2
= (2 x 83) m2=166 m2

Question 3:
Length of a room =9m,
Breadth of a room = 8m
And height of room = 6.5 m
∴ Area of 4 walls = Lateral surface area
= 2 (l+ b) x h
= [2 (9+8) x 6.5] m2
= (2 x 17 x 6.5) m2
=221 m2
∴ Area not be whitewashed = (area of 1 door) + (area of 2 windows)
= (2 x 1.5) m2 + (2 x 1.5 x 1) m2
= 3m+ 3m=6m2
∴ Area to be whitewashed = (221-6) m2 =215 m2
∴ Cost of whitewashing the walls at the rate of Rs.6.40 per
Square meter = Rs. (6.40 x 215) = Rs. 1376

Question 4: Question 5: Question 6: Question 7: Question 8: Question 9: Question 10: Question 11: Question 12: Question 13: Question 14: Question 15: Question 16: Question 17: Question 18: Question 19: Question 20: ### RS Aggarwal Solutions Class 9 Chapter 13Exercise 13B

Question 1: Question 2: Question 3: Question 4: Question 5: Question 6: Question 7: Question 8: Question 9: Question 10: Question 11: Question 12: Question 13: Question 14: Question 15: Question 16: Question 17: Question 18: ### RS Aggarwal Solutions Class 9 Chapter 13Exercise 13C

Question 1: Question 2: Question 3: Question 5: Question 6: Question 7: Question 8: Question 9: Question 10: Question 11: Question 12: Question 13: Question 14: Question 15: Question 16: Question 17: Question 18: ### RS Aggarwal Solutions Class 9 Chapter 13Exercise 13D

Question 1: Question 2: Question 3: Question 4: Question 5: Question 6: Question 7: Question 8: Question 9: Question 10: Question 11: Question 12: Question 13: Question 14: Question 15: Question 16: Question 17: Question 18: Question 19: Question 20: Question 21: Question 22: Question 23: All Chapter RS Aggarwal Solutions For Class 9 Maths

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All Subject NCERT Exemplar Problems Solutions For Class 9

All Subject NCERT Solutions For Class 9

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